How do you simplify #i^(-43)+i^(-32)# ?

Answer 1

#i^(-43)+i^(-32) = i+1#

Look at the first few non-negative powers of #i#:
#i^0 = 1#
#i^1 = i#
#i^2 = -1#
#i^3 = -i#
#i^4 = 1#
Basically this pattern: #1, i, -1, -i# repeats every #4# powers.
In terms of angles, multiplying by #i# is an anticlockwise rotation of #pi/2# in the complex plane. So after #4# rotations we are back facing the same way.

So in general we can write:

#{ (i^(4n) = 1), (i^(4n+1) = i), (i^(4n+2) = -1), (i^(4n+3) = -i) :}#
which holds for any integer #n#.

Now:

#-43 = -44+1 = 4(-11)+1#
#-32 = -32+0 = 4(-8)+0#

So:

#i^(-43)+i^(-32) = i+1#
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Answer 2

To simplify ( i^{-43} + i^{-32} ), we first need to recall the properties of the imaginary unit, ( i ). The imaginary unit ( i ) is defined as ( \sqrt{-1} ), and it follows the pattern: [ i^1 = i, \ i^2 = -1, \ i^3 = -i, \ i^4 = 1, \ i^5 = i, \ \text{and so on.} ]

Since the powers of ( i ) repeat every four terms, we can simplify the given expression by finding the remainder when each exponent is divided by 4: [ i^{-43} = i^{(-4 \times 10) - 3} = i^{-3}, ] [ i^{-32} = i^{(-4 \times 8) + 0} = i^0. ]

Now, using the pattern of ( i ) mentioned earlier: [ i^{-3} = -i, ] [ i^0 = 1. ]

Finally, we add the simplified terms: [ i^{-43} + i^{-32} = -i + 1. ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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