# If #3.06*g# #"strontium chromate"# is added to #1/2*L# of water, what is the UNDISSOLVED mass of salt?

We interrogate the equilibrium:

I get approx.

Which leads to a dissolved mass of............

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To find the undissolved mass of salt, we need to determine how much of the salt dissolves in the water. The solubility of strontium chromate in water at room temperature is approximately 0.68 grams per 100 milliliters of water. So, for 1/2 L (500 mL) of water, the maximum amount of strontium chromate that can dissolve is 3.4 grams. Since 3.06 grams of strontium chromate is added, the amount dissolved will be 3.06 grams. Therefore, the undissolved mass of salt is 3.06 grams.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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