What is the pressure in atmospheres, if the pressure is reported to be #854*mm*Hg#?

Answer 1

I do not know why we seem to be getting a lot of questions that quote pressures of #>760*mm*Hg............#

One atmosphere of pressure will support of column of mercury that is #760*mm# high. And thus we can use a colume on mercury to measure pressures that ARE LESS than #1*atm#, i.e #<760*mm*Hg#.
Given your problem, I suppose we could state that #854*"Torr"-=(854*"mm Hg")/(760 *"mm Hg"*atm^-1)=1.12*atm#. I really find the use of these units objectionable, because if you get a mercury spill in the lab, you have a major clean-up job, and guess who is going to do it?
And thus your question has not been consistently proposed. The pressure is LOWER at #1.12*atm#; i.e. it is expanded not compressed. Would you review this problem?
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Answer 2

The pressure is approximately 1.12 atmospheres.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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