Home > Chemistry > Molarity

A #16g# mass of sodium hydroxide is dissolved in enough water to give #2.0L# of solution. What is the concentration of the solution in #mol*L^-1#?

Answer 1

Peyton Adams

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"=#

#"Molarity"# #=# #((16.0*cancelg)/(40.0*cancelg*mol^-1))/(2.0*L)=0.20*mol*L^-1#.

Note how the units cancel to give the required units of concentration, i.e. #mol*L^-1#:

#((cancelg)/(*cancelg*mol^-1))/(L)=mol*L^-1#, i.e. #1/x^-1# #=# #1/(1/x)# #=# #x# as required...........

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Naomi Aronson

Concentration of the solution = moles of solute / volume of solution (in liters). Moles of NaOH = mass / molar mass. Molar mass of NaOH = 22.99 g/mol (Na) + 15.9994 g/mol (O) + 1.00794 g/mol (H). Concentration = (16 g / molar mass of NaOH) / 2.0 L.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

A #16*g# mass of sodium hydroxide is dissolved in enough water to give #2.0*L# of solution. What is the concentration of the solution in #mol*L^-1#?

A #16g# mass of sodium hydroxide is dissolved in enough water to give #2.0L# of solution. What is the concentration of the solution in #mol*L^-1#?