# What is the MacLaurin Series for #sin(2x)ln(1+x)#?

##
(portions of this question have been edited or deleted!)

(portions of this question have been edited or deleted!)

The given series is incorrect.

The correct series is:

# sin(2x)ln(1+x) = 2x^2 - x^3 - 2/3x^4 +1/6x^5 + ... #

The series that is provided is not correct.

Let:

Thus, we have the aforementioned, reputable series:

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you find the taylor series for #y=(e^x)cos(x)#?
- How do you use the binomial theorem to find the Maclaurin series for the function #y=f(x)# ?
- How do you find the Maclaurin series for # f(x) = x^2e^(-x)# centered at 0?
- What is the radius of convergence of #sum_1^oo x/n#?
- How do you find the maclaurin series expansion of #ln((1+x)/(1-x))#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7