How many ions result from the dissolution of a #11.1*g# mass of calcium chloride in water?

Answer 1

Approx. #1.81xx10^23# ions

The string "Moles of calcium chloride" is equivalent to (11.1g)/(110.98gmol^-1) = 0.100mol.

Consequently, in resolution:

#CaCl_2(s) + "excess "H_2OrarrCa^(2+) + 2Cl^(-)#, there are #0.100*mol# #Ca^(2+)# ions, and #0.200*mol# #Cl^(-)# ions, i.e. #0.300*mol# of ions...........

And #0.300*molxxN_A=0.300*molxx6.022xx10^23*mol^-1#

#1.81xx10^23# ions..........

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Answer 2

Caleb Adams

When 11.1 g of calcium chloride dissolves in water, it produces approximately 0.1 moles of calcium ions and 0.2 moles of chloride ions. Therefore, the dissolution results in 0.1 calcium ions and 0.2 chloride ions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.