Solve for #x#? #3(x-4)<12 or 4(x+3)<12#
Let's solve them individually and see what we get:
Equation 1
Equation 2
Putting it together
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To solve for (x), you need to solve each inequality separately.
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(3(x - 4) < 12): [3(x - 4) < 12] [3x - 12 < 12] [3x < 12 + 12] [3x < 24] [x < \frac{24}{3}] [x < 8]
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(4(x + 3) < 12): [4(x + 3) < 12] [4x + 12 < 12] [4x < 12 - 12] [4x < 0] [x < 0]
So, the solutions for (x) are: [x < 8] for the first inequality, and [x < 0] for the second inequality.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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