How do you solve: $-2x^2 + 8 = 0#?

Answer 1

See the entire solution process below:

First, subtract #color(red)(8)# from each side of the equation to isolate the #x# term while keeping the equation balanced:
#-2x^2 + 8 - color(red)(8) = 0 - color(red)(8)#
#-2x^2 + 0 = -8#
#-2x^2 = -8#
Next, divide each side of the equation by #color(red)(-2)# to isolate #x^2# while keeping the equation balanced:
#(-2x^2)/color(red)(-2) = (-8)/color(red)(-2)#
#(color(red)(cancel(color(black)(-2)))x^2)/cancel(color(red)(-2)) = 4#
#x^2 = 4#
Now, take the square root of each side of the equation to solve for #x# while keeping the equation balanced. Remember, the square root of a number produces both a negative and positive result:
#sqrt(x^2) = sqrt(4)#
#x = +-2#
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Answer 2

#x = 2 ,-2#

#-2 x^2 + 8 =0#
subtract #-8# to both sides #-2 x^2 + 8 - 8=0 -8# #-2 x^2 = -8#
divide #-23# to both sides #(-2 x^2) /-2 = -8/-2# #x^2 = 4#
square root both sides #sqrt (x^2) = sqrt 4# #x = +-2#
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Answer 3

To solve the equation 2x2+8=0-2x^2 + 8 = 0, follow these steps:

  1. Subtract 8 from both sides: 2x2=8-2x^2 = -8.
  2. Divide both sides by 2-2: x2=4x^2 = 4.
  3. Take the square root of both sides: x=±2x = \pm 2.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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