How do you solve: $-2x^2 + 8 = 0#?
See the entire solution process below:
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To solve the equation , follow these steps:
- Subtract 8 from both sides: .
- Divide both sides by : .
- Take the square root of both sides: .
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you solve using the completing the square method #x^2-8x+15=0#?

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