How is #"Mohr's salt"# oxidized by #"potassium permanganate"# to give #Fe^(3+)# and #Mn^(2+)#? How is #"hydrogen peroxide"# oxidized by the same reagent to give #"dioxygen gas"#?
Well, in the first scenario,
Which (I think) is balanced with respect to mass and charge.
Again, you can very accurately determine the stoichiometric endpoints by means of the pronounced colour change.
If I have missed the point of your question, would you clarify?
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"Mohr's salt" (ammonium iron(II) sulfate hexahydrate, (NH4)2Fe(SO4)2·6H2O) is oxidized by "potassium permanganate" (KMnO4) to give Fe^(3+) and Mn^(2+) through a redox reaction. The permanganate ion (MnO4^-) is reduced to Mn^(2+) while iron(II) is oxidized to iron(III). The reaction proceeds as follows:
5 Fe^(2+) + MnO4^- + 8 H^+ → 5 Fe^(3+) + Mn^(2+) + 4 H2O
Hydrogen peroxide (H2O2) is oxidized by potassium permanganate to give dioxygen gas (O2). In this reaction, permanganate ion (MnO4^-) is reduced to manganese dioxide (MnO2), and hydrogen peroxide is oxidized to dioxygen gas. The balanced equation is:
2 KMnO4 + 3 H2O2 → 2 MnO2 + 2 KOH + 3 O2
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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