If #y=2x+tanx#, find #y'''# third derivative of #y#?
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To find the third derivative of y = 2x + tan(x), we differentiate the function three times with respect to x.
y' = 2 + sec^2(x)
y'' = 2sec^2(x)tan(x)
y''' = 2[2sec^2(x)tan(x)tan(x) + sec^2(x)sec^2(x)]
y''' = 2[2tan^2(x)sec^2(x) + sec^4(x)]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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