What is the product of the reaction between 2-bromo-2-methylpentane and sodium ethoxide in ethanol?
Here's what I get.
The tertiary substrate favours an
The strong base favours elimination, so we draw an
The strongest base in the reaction mixture is the ethoxide ion, formed by the reaction
The mechanism is
Step 1. The Step 2. The strong base removes a β-hydrogen atom to form the most stable (most highly-substituted) alkene.
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The product is 2-methyl-2-pentene.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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