How does #H_3COCH_2CH_2CO_2H# dissociate as an acid?

Answer 1

For #H_3COCH_2CH_2CO_2H#?

#"3-methoxypropionic acid"# dissociates according to:
#H_3COCH_2CH_2CO_2H + H_2O rightleftharpoons H_3COCH_2CH_2CO_2^(-) + H_3O^+#
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Answer 2

The compound H₃COCH₂CH₂CO₂H dissociates as an acid by releasing a proton from the carboxylic acid group (COOH), resulting in the formation of the conjugate base H₃COCH₂CH₂CO₂⁻ and a hydronium ion (H₃O⁺).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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