#K_b# for #"acetoaminophen"# is #4.1xx10^-4#. What is #[HO^-]# for a solution of #"acetoaminophen"# at #0.910*mol*L^-1# concentration?
The expression for base association is written in the standard manner:
#x_2=sqrt(K_bxx (0.910-0.019))=sqrt(4.1xx10^-4xx(0.910-0.019))=0.019molL^-1#
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[ [HO^-] = \sqrt{K_b \cdot \text{concentration}} = \sqrt{4.1 \times 10^{-4} \cdot 0.910} ] [ [HO^-] \approx 0.018 , \text{mol/L} ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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