We have points A (-1,2) and B (1,6). Find the following?
a. the gradient,
b. the line equation in point-slope form,
c. the gradient of a line perpendicular to the one in b that runs through point (-2,5),
d. the point where the two lines intersect,
e. the points where the line found in b intersects with the curve #y=x^2+1#
a. the gradient,
b. the line equation in point-slope form,
c. the gradient of a line perpendicular to the one in b that runs through point (-2,5),
d. the point where the two lines intersect,
e. the points where the line found in b intersects with the curve
The 2 points here are A(-1 ,2) and B(1 ,6)
For a point on the line, use either (-1 ,2) or (1 ,6)
distributing the bracket and simplifying gives an alternative version of the equation.
graph{(y-(2x+4))(y-(-1/2x+4))=0 [-9.96, 10.04, -2, 9.4]}
And we can again see that in the graph:
graph{(y-(x^2+1))(y-(2x+4))=0 [-11.82, 16.66, -0.76, 13.48]}
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Please specify what you would like to find regarding the points A (-1,2) and B (1,6).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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