What mass of caustic soda are required to prepare a solution of #100*mL# volume that is #1.0*mol*L^-1# with respect to #NaOH#?

Answer 1

A mass of #4.0*g# #"sodium hydroxide"# is required............

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#
Here, #"concentration"# #=# #1.0*mol*L^-1#, #"volume"# #=# #100*mL#.
And thus #"moles of solute"# #=# #"Concentration "xx" Volume"#
#=1*mol*L^-1xx100xx10^-3L=0.100*mol#.
And thus #"mass of solute"# #=# #"number of moles "xx" molar mass"#
#=0.100*molxx40.0*g*mol^-1=??*g#.
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Answer 2

To prepare a solution of 100 mL volume that is 1.0 mol/L^-1 with respect to NaOH, you would need 4.0 grams of caustic soda (NaOH).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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