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If #f(x) = 2 - x - x^2#, then what is #f(–1)+ f(0)#?

Answer 1

Eva Adamson

The answer is 4.

If #f(x)=2-x-x^2#, then

#f("-1")+f(0)# #=[2-("-1")-("-1")^2] + [2-(0)-(0)^2]# #=[2+1-1] + [2]# #=4#

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Answer 2

Hazel Anglin

To find ( f(-1) + f(0) ), first substitute ( x = -1 ) into the function ( f(x) ) and then substitute ( x = 0 ) into the function ( f(x) ), and then add the results together.

[ f(-1) = 2 - (-1) - (-1)^2 ] [ f(-1) = 2 + 1 - 1 ] [ f(-1) = 2 ]

[ f(0) = 2 - 0 - 0^2 ] [ f(0) = 2 ]

Now, add ( f(-1) ) and ( f(0) ):

[ f(-1) + f(0) = 2 + 2 ] [ f(-1) + f(0) = 4 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.