When octane is completely combusted, what is the whole number ratio between the dioxygen reactant, and the product hydrogens?

Answer 1

Well, clearly it's #25:18#.

You have the balanced chemical equation:

#C_8H_18(l) + 25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#

And the stoichiometry precisely specifies that #"25 equiv"# of oxygen gas are required for complete combustion of #"2 equiv"# of #"octane"#, to give #"16 equiv"# of #"carbon dioxide"# and #"18 equiv"# of #"water."#

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Answer 2

Henry Antrim

The whole number ratio between dioxygen (O2) and hydrogen (H2O) in the complete combustion of octane (C8H18) is 25:9.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.