A #100*mL# volume of #2.0*mol*L^-1# hydrochloric acid titrated a sample of metal carbonate. What is the equivalent weight of the metal?

Question

A #100*mL# volume of #2.0*mol*L^-1# hydrochloric acid titrated a sample of metal carbonate.  What is the equivalent weight of the metal?

Noah Aldrich · Accepted Answer

The equivalent weight of the metal is #100.0*g*mol^-1#

We must first obtain a chemical equation:

#MCO_3(s) + 2HCl(aq) rarr MCl_2(aq) + H_2O(l) + CO_2(g)uarr#

#"Moles of HCl"=0.100*Lxx2*mol*L^-1=0.200*mol#

Given the equation, the #"metal carbonate"# represents #0.100*mol#, and thus, given the equation, the equivalent weight of the #"metal carbonate"# is #100.0*g*mol^-1#. This equivalent weight is CONSISTENT with a formula of #CaCO_3#.

Jeremiah Adams · Answer

Equivalent weight of metal is 20 g/eq

For HCl Molarity = Normality Gram equivalents of HCl = Normality × Volume in litres #= 2 N × 100 × 10^-3 L# #= 0.2# eq For complete neutralisation Gram equivalents of HCl = Gram equivalents of metal carbonate Equivalent weight of metal carbonate #= text(Weight of metal carbonate) / text(Gram equivalents of metal carbonate)# #= (10 g) / (0.2 text(eq)) = 50# g/eq Equivalent weight of carbonate #(CO_3^(2-)) = (12 + (3 × 16))/2 = 30# g/eq Equivalent weight of metal carbonate = Equivalent weight of metal + Equivalent weight of carbonate 50 g/eq = x + 30 g/eq x = 20 g/eq ∴ Equivalent weight of metal is 20 g/eq

Owen Ambrose · Answer

The number of moles of #HCL#  reacted with Carbonate salt is  #="molarity of acid" xx " volume of acid in L"# #=2 mol"/"Lxx 0.1L=0.2mol# So the mass of #HCl# reacted #= 0.2xx36.5g#, where molar mass of #HCl =36.5g"/"mol# Now we know from the law of equivalent proportion that the ratio of masses of two reacting substances for neutralization is equal to the ratio of their equivalent masses. Hence we can say  #"Equivalent mass of metal carboate" /("Equivalent mas of "HCl)="Reacting mass of metal carboate" /("Equivalent mas of "HCl)# #=>("Equivalent mass of metal (x=?)+ equivalent mass of "CO_3^(2-))/("Equivalent mas of "HCl)=(0.2xx36.5)/36.5# #=>(x + 30"g/equiv")/(36.5"g/equiv")=(10g)/(0.2xx36.5g)# #=>color(red)(x=20"g/equiv")# Please note 
Equivalent mass of #CO_3^(2-)= (" formula mass of " 
CO_3^(2-))/"valency "# #=(12+3xx16)/2=30"g/equiv"#

Axel Alvarado · Answer

undefined Equivalent weight = (Molar mass of metal carbonate) / (moles of HCl used in the reaction)