How is the partial pressure of a component gas proportional to the percentage composition (by molar quantity) to the gaseous mixture?

Question

Caleb Adams · Accepted Answer

The partial pressure of each gas is proportional to the given percentage.

#P_"Total"=P_"methane"+P_"ethane"+P_"propane"+P_"butane"#. Given the Ideal Gas equation, #P_"Total"=(n_"Total"RT)/V# But #n_"Total"=(n_"methane"+n_"ethane"+n_"propane"+n_"butane")# And so, #P_"Total"=(n_"methane"+n_"ethane"+n_"propane"+n_"butane")(RT)/V# You have the percentage composition of the gas, and you simply multiply #P_"Total"# by the individual percentages to get the partial pressure of each gas. Thus #P_"methane"=1.48*atmxx94%=??*atm#. And you can work out these pressures individually. See here for another example.

Jose Ayala · Answer

undefined The partial pressure of a component gas is proportional to its percentage composition in the gaseous mixture by molar quantity according to Dalton's Law of Partial Pressures.