How do you solve #80 - 2w >= 50#?

Answer 1

#w <= 15#

First, subtract #color(red)(80)# from each side of the inequality to isolate the #w# term while keeping the inequality balanced:
#80 - color(red)(80) - 2w >= 50 - color(red)(80)#
#0 - 2w >= -30#
#-2w >= -30#
Now, divide each side of the inequality by #color(blue)(-2)# to solve for #w# while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative term we must reverse the inequality condition:
#(-2w)/color(blue)(-2) color(red)(<=) (-30)/color(blue)(-2)#
#(color(blue)(cancel(color(black)(-2)))w)/cancel(color(blue)(-2)) color(red)(<=) 15#
#w <= 15#
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Answer 2

To solve the inequality 80 - 2w ≥ 50, follow these steps:

  1. Subtract 80 from both sides to isolate the term with the variable: 80 - 80 - 2w ≥ 50 - 80 -2w ≥ -30

  2. Divide both sides by -2. Remember to flip the inequality sign when dividing by a negative number: -2w / -2 ≤ -30 / -2 w ≤ 15

Therefore, the solution to the inequality is w ≤ 15.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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