What is the mass of a #1.26xx10^-4*mol# quantity of acetic acid?

Answer 1

#"In acetic acid,"# #H_3"CCO"_2H#?

Now, the basic equation is #"moles"# #=# #"mass"/"molar mass"#....and thus #"mass"# #=# #"moles"# #xx# #"molar mass"#.

Thus, in this instance,

#"mass"# #=# #1.26xx10^-4*cancel(mol)xx60.05*g*cancel(mol^-1)=7.60*mg#.

This expression is undoubtedly dimensionally consistent. I specifically requested a response in mass units, and the computation provided those units.

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Answer 2

Peyton Adams

The mass of #"CH"_3"COOH"# is #"0.00757 g"#.

Divide the moles by the molar mass.

The molar mass of acetic acid #("CH"_3"COOH")# is #"60.052 g/mol"#. https://tutor.hix.ai

#1.26xx10^(-4)color(red)cancel(color(black)("mol CH"_3"COOH"))xx(60.052"g CH"_3"COOH")/(1color(red)cancel(color(black)("mol CH"_3"COOH")))="0.00757 g CH"_3"COOH"# (rounded to three significant figures)

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Answer 3

Jeremiah Adams

The mass of a (1.26 \times 10^{-4}) mol quantity of acetic acid (CH₃COOH) is approximately 2.52 grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.