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What mass is associated with a #17.8*mL# volume of aluminum metal?

Answer 1

Wyatt Atkins

This site reports that #rho_"Al"=2.7*g*cm^-3#

We know that #rho#, #"density"="unit mass"/"unit volume"#

And thus #"mass"="density"xx"volume"#

And thus, since #1*mL-=1*cm^3#, we take the product........

#"volume"xx"density"="mass"#

So #"mass"=rhoxx"volume"#

#=2.7*g*cancel(mL^-1)xx17.8*cancel(mL)=48*g#

We want an answer in grams, and the product provides us with an answer in grams. The product is dimensionally consistent.

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Answer 2

Luna Chen

The mass associated with a 17.8 mL volume of aluminum metal can be determined using its density, which is approximately 2.7 g/mL. The mass would be 48.06 grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.