How many moles are present in #7.25xx10^25# #"carbon dioxide molecules"#?

Answer 1

Well one mole of stuff, any stuff, including carbon dioxide, specifies #6.022xx10^23# individual items of that stuff.

We then calculate the quotient as follows:

#(7.2xx10^25*"carbon dioxide molecules")/(6.022xx10^23*"carbon dioxide molecules"*mol^-1)#
#~=120*mol# #"carbon dioxide"#.
This is dimensionally consistent, because we get an answer with units #1/(mol^-1)=1/(1/"mol")=mol# as required.

Do you concur?

What is the mass of this carbon dioxide quantity?

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Answer 2

To determine the number of moles present in (7.25 \times 10^{25}) carbon dioxide molecules, you would divide the given number of molecules by Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules/mol. So, (7.25 \times 10^{25}) molecules divided by (6.022 \times 10^{23}) molecules/mol equals approximately (12.05) moles of carbon dioxide.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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