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What is the molarity of a solution of containing a mass of #250g# sodium chloride in a volume of #775mL# water?

Answer 1

Peyton Adams

We use the relationship,

#"Molarity"# #=# #"Moles of solute"/"Volume of solution (L)"~=6*mol*L^-1#

Consequently,

#"Molarity"=(250.0*g)/(58.44*g*mol^-1)xx1/(775*mLxx10^-3*L*mL^-1)#

#=??mol*L^-1#

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Answer 2

Noah Aldrich

To find the molarity of the solution, we need to first convert the mass of sodium chloride from grams to moles using its molar mass (58.44 g/mol). Then, we divide the number of moles by the volume of the solution in liters.

Molar mass of NaCl = 58.44 g/mol

Number of moles of NaCl = mass / molar mass = 250 g / 58.44 g/mol ≈ 4.28 mol

Volume of solution = 775 mL = 775/1000 L = 0.775 L

Molarity (M) = moles of solute / volume of solution in liters = 4.28 mol / 0.775 L ≈ 5.52 M

So, the molarity of the solution is approximately 5.52 M.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

What is the molarity of a solution of containing a mass of #250*g# sodium chloride in a volume of #775*mL# water?

What is the molarity of a solution of containing a mass of #250g# sodium chloride in a volume of #775mL# water?