How does #"silver nitrate"# react with #"sodium oxalate"# in aqueous solution?

Answer 1

#"2AgNO"_3(aq) + "Na"_2"C"_2"O"_4(aq) rarr "Ag"_2"C"_2"O"_4(s) + "2NaNO"_3(aq)#

Additionally, the net ionic equation is as follows (since the sodium and nitrate ions are essentially just passengers):

#"2Ag"^(+) + "C"_2"O"_4^(2-) rarr "Ag"_2"C"_2"O"_4(s)darr#
#"Silver oxalate"# is a rather insoluble beast. I think the material is shock sensitive; so you should avoid making gram quantities, or drying the precipitate.
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Answer 2

The balanced chemical equation is: [ AgNO_3 + Na_2C_2O_4 \rightarrow Ag_2C_2O_4 + 2NaNO_3 ] Silver nitrate + sodium oxalate reacts in an aqueous solution to form silver oxalate and sodium nitrate.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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