How do we rationalize the aqueous solubilities of organic and inorganic materials?

Answer 1

The important distinction is between #"molecular"# and #"non-molecular"# bonding.

Certain salts have some solubility in aqueous solvents: sodium chloride dissolves in water to some extent, even tho its structure is non-molecular, and the bonds that form the ionic lattice are strong. As a polar solvent, water is capable of solvating individual ions, and break up the ionic lattice to form so-called aquated ions, #"[Na(OH"_2)_6]^+#, which we would normally represent as #"Na"^+(aq)# and #"Cl"^(-)(aq)#. Organic solvents tend to offer poor solvation of ionic species, and as a result, such salts tend to have miniscule solubility in these media.
On the other hand, giant covalent structures, such as those of #C_"graphite"# or #C_"diamond"# have strong #C-C# bonds in an infinite array across the entire solid, for which solvation by water cannot energetically compensate. These materials ALSO have exceptionally poor to zero solubility in organic solvents for the same reasons.
Of course, some organic molecules, such as #"sucrose"#, have substantial water solubility due to the presence of polar, hydrogen-bonding groups on the sugar molecule. Other organic molecules, such as the alkane series, will have limited water solubility, as there are no polar groups on the hydrocarbyl chain that could interact with the water molecule.

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Answer 2

The solubility of organic compounds in water is primarily determined by their polarity. Polar organic compounds, such as alcohols and carboxylic acids, tend to be soluble in water due to the ability to form hydrogen bonds with water molecules. In contrast, nonpolar organic compounds, such as hydrocarbons, are generally insoluble in water. Inorganic materials' solubilities in water depend on factors such as the nature of the ionic bonds and the hydration energy of ions. Ionic compounds, such as salts, dissociate into ions when dissolved in water, and their solubility depends on the balance between the lattice energy of the solid and the hydration energy of the ions. Covalent inorganic compounds, such as gases and some oxides, may or may not be soluble in water depending on their polarity and ability to form hydrogen bonds.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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