A rectangle has three of its vertices at points #(3,4), # #(5,–4),# and #(–7, –7).# What is the #y# coordinate of the unknown vertex?

Answer 1

The #y#-coordinate of the fourth vertex is #1#.

The given points can be drawn in the #xy#-plane as follows: graph{((x-3)^2+(y-4)^2-0.05)((x-5)^2+(y+4)^2-0.05)((x+7)^2+(y+7)^2-0.05)=0 [-14.95, 13.52, -8.37, 5.87]}
From here, it is easy to visualize roughly where the fourth vertex will be—somewhere in #"Quadrant II"#.
Since rectangles are composed of two sets of parallel sides, the #y# distance between two adjacent points will be the same as the #y# distance between the other two points.
What does this mean? Well, the point #(3,4)# is 8 up from its neighbour #(5,"-"4)# (since #4-"(-4)"=8#), so the fourth vertex will also be 8 up from #("-7","-7")#. And what is 8 up from -7? That's right: 1.
We can use this to find the #x#-coordinate as well; just use the #x#-coordinates instead of the #y#'s. The remaining vertex is at #("-9",1)#.

Hope this helps!

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Answer 2

#(-9, 1#)

Use :

The vector #(x_1, y_1) to (x_2, y_2)# is # < x_2-x_1, y_2-y_1>#.

The vertices are labelled

#A( 3, 4 ), B( 5, -4 ), C(-7. -7) and D( x, y ).#.
Vector #AD = < x-3, y-4>#
= vector # BC=<-12, -3>#.

Solving,

(#x, y) = (-9, 1)#.
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Answer 3

To find the y-coordinate of the unknown vertex of the rectangle, we first need to determine the length of one of its sides. We can do this by calculating the distance between two known vertices. Let's choose the vertices (3,4) and (5,-4).

Using the distance formula, the distance between these two points is:

[ \sqrt{((5-3)^2 + (-4-4)^2)} = \sqrt{4^2 + 8^2} = \sqrt{16 + 64} = \sqrt{80} ]

Since a rectangle has equal opposite sides, this distance represents the length of one side of the rectangle.

Now, let's find the vector between the two known vertices: (3,4) and (5,-4). This vector will give us the direction from one point to the other.

[ \text{Vector} = (5-3, -4-4) = (2, -8) ]

To find the unknown vertex, we add this vector to one of the known vertices. Let's add it to the vertex (3,4):

[ \text{Unknown Vertex} = (3,4) + (2, -8) = (3+2, 4-8) = (5, -4) ]

So, the y-coordinate of the unknown vertex is -4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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