How would the reaction of a metal oxide with hydrogen gas occur?
This type of reaction could be inverted, meaning it could be naturally nonspontaneous. This would occur if the pure metal had a higher oxidation rate than hydrogen gas.
CHALLENGE: If sodium oxide were used instead of other oxide, how would this reaction be written? Would heat still be needed if high heat and pressure were still needed?
Typically, a naturally occurring spontaneous reaction would be:
which is why magnesium fires should never be put out with water because hydrogen gas is flammable.
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When a metal oxide reacts with hydrogen gas, it usually reduces to form the metal and water vapor (a process known as a reduction reaction). The specific reaction that occurs depends on the metal oxide that is involved. The hydrogen gas functions as a reducing agent by giving electrons to the metal oxide, which causes the oxygen atoms in the oxide to break their bonds with the metal atoms and form water vapor.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How does sodium oxide react with water?
- How are elements and compounds similar?
- How do you write a total ionic equation and a net ionic equation for this reaction? #HCl(aq) + NaOH (aq) -> NaCl (aq) + H_2O(l)#?
- How do you balance this chemical equation: #"Mg"_3"B"_2 + "H"_2"O" -> "Mg"("OH")_2 + "B"_2"H"_6#?
- Why do you need to balance a chemical equation?

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