You have a stock of two blends of dry mix sand and cement that you wish to blend to give you 10 tons at 40% cement content. ?

One of these mixes has 20% cement content and the other has 70% cement content. How many tons of each need to be mixed together to give you the target concentration and weight.

Answer 1

6 tons at 20% blend
4 tons at 70% blend

Target is a blend with 40% cement

Let the amount of 20% material be designated as #M_20# Let the amount of 70% material be designated as #M_70#
#M_20+M_70=10" "......... .......................Equation(1)#
#20%M_20+70%M_70 = 40%10" "............Equation(2)#
From #Eqn(1)" "M_20=10-M_70" "............Equation(1_a)#
Using #Eqn(1_a)# substitute for #M_20# in #Eqn(2)#
#color(white)("dddddddddd")color(green)(20/100(color(red)(M_20))+70/100M_70=40/100xx10#
#color(white)("dddd")color(white)("dd")20/100(color(red)(10-M_70))+70/100M_70=400/100#

Multiply both sides by 100 to get rid of the fraction

#color(white)("ddddddd")color(white)("dd")20(10-M_70)+70M_70=400#
#color(white)("ddddddddddddd")200color(white)("dddd")+50M_70=400#
#color(white)("dddddddddddddddddddddddd")color(blue)(M_70=(400-200)/50 = 4" tons")# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Thus #color(blue)(M_20=10-4=6" tons")#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ #color(brown)("Checking LHS - RHS is "40%xx10=4)#
#(20/100xx6)+(70/100xx4) =4#

LHS=RHS thus proven to be true

color(white)("d")

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Answer 2

To blend two dry mixtures to achieve a desired percentage of cement content, you can use the following formula:

(C_1 \times W_1 + C_2 \times W_2 = C_f \times W_f)

Where: (C_1) = Percentage of cement in blend 1 (W_1) = Weight of blend 1 (C_2) = Percentage of cement in blend 2 (W_2) = Weight of blend 2 (C_f) = Desired percentage of cement in the final blend (W_f) = Total weight of the final blend

Given: (C_1) = Cement content of blend 1 (unknown) (W_1) = Weight of blend 1 (unknown) (C_2) = Cement content of blend 2 (unknown) (W_2) = Weight of blend 2 (unknown) (C_f) = Desired cement content in the final blend (40% or 0.4) (W_f) = Total weight of the final blend (10 tons)

We have one equation and two unknowns, so we need another equation to solve for (C_1) and (W_1). If we have additional information about the blends, such as their cement content percentages or weights, we can use that information to solve the system of equations.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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