If the volume of an ideal gas at #"350 torr"# of pressure and #25^@ "C"# is #"450 L"#, at what temperature is its volume #"420 L"# and pressure #"830 torr"# in a sealed balloon?

Answer 1

386.6 degrees C

# (V_1 xx P_1)/T_1 = (V_2 xx P_2)/T_2#
# V_1 = 450# # P_1 = 350# # T_1 = 273 + 25 = 298 # temperature must be calculated in degrees K or absolute zero.
# V_2 = 420# # P_2 = 830# # T_2 = unknown ?#

putting these values into the equation gives

# (450 xx 350)/298 = (420 xx 830)/T_2# Solving for #T_2# gives
#T_2 = (420 xx 830 xx 298)/ (450 xx 350)# solving gives

#T_2 = 659.57333333 subtract 273 to bring back to degrees C and round off to four significant figures. gives

#T_2 = 386.6 #
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Answer 2

To find the temperature, use the combined gas law equation: ( P_1V_1/T_1 = P_2V_2/T_2 ). Rearrange the equation to solve for ( T_2 ): ( T_2 = (P_2V_2 * T_1)/(P_1V_1) ). Plug in the given values and solve for ( T_2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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