Is #pi^2# rational or irrational?

Answer 1

#pi^2# is irrational

#pi# is transcendental, meaning that it is not the root of any polynomial equation with integer coefficients.
Hence #pi^2# is transcendental and irrational too.
If #pi^2# were rational, then it would be the root of an equation of the form:
#ax+b = 0#
for some integers #a# and #b#
Then #pi# would be a root of the equation:
#ax^2+b = 0#
Since #pi# is not the root of any polynomial with integer coefficients, let alone a quadratic, this is not possible.
Further, if #pi^2# was the root of any polynomial equation with integer coefficients then #pi# would be the root of the same equation with each #x# replaced by #x^2#. So since #pi# is transcendental, so is #pi^2#.
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Answer 2

Pi squared (( \pi^2 )) is an irrational number.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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