We have three cars with four people in each car. If the car owner must occupy their own car, how many arrangements of the people are possible?

Answer 1

84

The number of combinations of #n# people taken #p# at a time is given by #""_nC_p = (n!)/(p!(n-p)!#

In this example, there are 3 cars each with 4 people in each. The people in each car are: 1 owner + 3 passengers

The owner is fixed per car so the number of arrangements (combinations) of the remaining 9 people is #""_9C_3#
#=(9!)/(3!*6!)#
#=(9xx8xx7)/(3xx2xx1)=84#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7