Home > Chemistry > Double Replacement Reactions

How does metathesis occur between silver(I) nitrate, and copper(II) choride in aqueous solution?

Answer 1

#2AgNO_3(aq) +CuCl_2(aq) rarr Cu(NO_3)_2(aq) + 2AgCl(s)darr#

This is an expensive method of producing copper salts because copper nitrate stays in solution while the silver halide precipitates as a curdy white solid.

Using lead salt might be a more effective method.

#Pb(NO_3)_2(aq) +CuCl_2(aq) rarr Cu(NO_3)_2(aq) + PbCl_2(s)darr#

At least this way you don't get silver salts, which have a tendency to reduce. #PbCl_2# is fairly insoluble in cold water, and non-redox active.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Axel Alvarado

Silver(I) nitrate (AgNO3) and copper(II) chloride (CuCl2) undergo metathesis in an aqueous solution when the copper ion (Cu²⁺) from copper chloride combines with the nitrate ion (NO3⁻) from silver nitrate to form copper(II) nitrate (Cu(NO3)2), which stays dissolved in the solution, and the silver ion (Ag⁺) from silver nitrate reacts with the chloride ion (Cl⁻) from copper chloride to form silver chloride (AgCl), which precipitates out of solution.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.