Home > Chemistry > Molarity

#18.9g# of ammonium nitrate is dissolved in a #855mL# volume of water. What is the concentration of the salt?

Answer 1

Peyton Adams

#"Molarity"="Moles of solute"/"Volume of solution"#

And thus #"molarity"# #=# #((18.9*g)/(80.04*g*mol^-1))/(0.855*L)# #=# #??*mol*L^-1#.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Wyatt Atkins

Concentration of the salt (NH₄NO₃) = mass of salt (g) / volume of solution (L)

Concentration = 18.9 g / 0.855 L = 22.11 g/L

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Trending questions

Not the question you need?

HIX Tutor

Solve ANY homework problem with a smart AI

98% accuracy study help
Covers math, physics, chemistry, biology, and more
Step-by-step, in-depth guides
Readily available 24/7

#18.9*g# of ammonium nitrate is dissolved in a #855*mL# volume of water. What is the concentration of the salt?

#18.9g# of ammonium nitrate is dissolved in a #855mL# volume of water. What is the concentration of the salt?