What is the balanced equation that represents the combustion of glycerol by potassium permanganate?

Answer 1

#14KMnO_4(s) + 4C_3H_5(OH)_3(l) rarr 5CO_2(g) + 7K_2CO_3(s) + 7Mn_2O_3(s)+16H_2O(l)#

This is stoichiometrically balanced, as indeed it must be if it reflects chemical reality. The oxidation products are carbon dioxide, and potassium carbonate; the reduction products are a #Mn(III)# oxide. It is a spectacular reaction to do, but do it safely! I have seen a few fires when the reaction does not immediately commence, and the reaction mixture is placed into a waste container, where of course it does commence.
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Answer 2

The balanced equation for the combustion of glycerol (C3H8O3) by potassium permanganate (KMnO4) is:

8 KMnO4 + 22 H2O + 30 C3H8O3 -> 8 MnO2 + 20 KOH + 45 CO2 + 68 H2O

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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