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How do you graph the line #y = -1/3x - 7#?

Answer 1

Savannah Aguilar

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (-1/3 xx 0) - 7#

#y = 0 - 7#

#y = -7# or #(0, -7)#

Second Point: For #x = 3#

#y = (-1/3 xx 3) - 7#

#y = -3/3 - 7#

#y = -1 - 7#

#y = -8# or #(3, -8)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+7)^2-0.075)((x-3)^2+(y+8)^2-0.075)=0 [-20, 20, -15, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + (1/3)x + 7)(x^2+(y+7)^2-0.075)((x-3)^2+(y+8)^2-0.075)=0 [-20, 20, -15, 5]}

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Answer 2

Ella Armstrong

To graph the line y = -1/3x - 7, plot the y-intercept at (0, -7), which is where the line crosses the y-axis. Then, use the slope of -1/3 to find another point. Since the slope is -1/3, this means that for every increase of 3 units to the right, the line goes down by 1 unit. So, from the y-intercept (0, -7), move 3 units to the right and 1 unit down to get the next point, and so on. Drawing a line through these points will represent the graph of y = -1/3x - 7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.