How many moles of silver(I) bromide are produced when #6.45# moles of sodium bromide take part in the reaction?

#"NaBr"_ ((aq)) + "AgNO"_ (3(aq)) -> "AgBr"_ ((s)) darr + "NaNO"_ (3(aq))#

Answer 1

#"6.45 moles AgBr"#

The thing to remember about balanced chemical equations is that they tell you the mole ratios in which the reactants and the products find themselves for a given chemical equation.

More specifically, the balanced chemical equation tells you how many moles of each reactant will react with each other and how many moles of products will be produced as a result.

In this case, the balanced chemical equation that describes this double replacement reaction looks like this

#"NaBr"_ ((aq)) + "AgNO"_ (3(aq)) -> "AgBr"_ ((s)) darr + "NaNO"_ (3(aq))#
Stoichiometric coefficients of #1# are omitted from the balanced chemical equation, but in your case the problem wants to give you a hand and lists them
#1"NaBr"_ ((aq)) + 1"AgNO"_ (3(aq)) -> 1"AgBr"_ ((s)) darr + 1"NaNO"_ (3(aq))#
So, this tells you that for every mole of sodium bromide, #"NaBr"#, that takes part in the reaction you get #1# mole of silver bromide, #"AgBr"# #-># the two compounds are in a #1:1# mole ratio.
Since you know that #6.45# moles of sodium bromide are available for the reaction, and assuming that all of them react, you can say that the reaction will produce
#6.45 color(red)(cancel(color(black)("moles NaBr"))) * "1 mole AgBr"/(1color(red)(cancel(color(black)("mole NaBr")))) = color(green)(|bar(ul(color(white)(a/a)color(black)("6.45 moles AgBr")color(white)(a/a)|)))#
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Answer 2

To find the number of moles of silver(I) bromide produced, we need to determine the stoichiometric ratio between sodium bromide and silver(I) bromide in the reaction.

The balanced chemical equation for the reaction would be:

2 NaBr + AgNO3 -> 2 NaNO3 + AgBr

From the balanced equation, we see that 2 moles of NaBr react with 1 mole of AgNO3 to produce 2 moles of AgBr.

So, the mole ratio of NaBr to AgBr is 2:2, or simply 1:1.

Given that 6.45 moles of sodium bromide are involved in the reaction, the same number of moles of silver(I) bromide will be produced.

Therefore, 6.45 moles of silver(I) bromide are produced when 6.45 moles of sodium bromide take part in the reaction.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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