What must the temperature, pressure, and volume units be in any gas law?

Answer 1

The temperature must be in 'K for the ratios to work out. The pressure and volume units are arbitrary, as long as they are consistent.

However, keep in mind that you cannot mix the units and get the right answers when using them to calculate actual molar values; you must use the correct units and conversion factors.

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Answer 2

The combination of all these laws can be derived from

#\mathbf(PV = nRT),#

by choosing two or three variables to keep constant, so whatever applies to the ideal gas law applies to the rest.

For all of these laws, the volume, temperature, and pressure must match the units of the universal gas constant you choose so you get the answer in the right units.

The universal gas constant in gas law problems is often used as:

(1)

#R = (PV)/(nT)#

Looking at only the units, we see:

#("L"cdot"atm")/("mol"cdot"K") = (stackrel(V)overbrace("L")cdot stackrel(P)overbrace("atm"))/(stackrel(n)overbrace("mol")cdot stackrel(T)overbrace("K"))#
So these are clearly equivalent units. That means if you use (1), then volume is in #\mathbf("L")#, temperature is in #\mathbf("K")#, and pressure is in #\mathbf("atm")#.

(2)

#R = (PV)/(nT)#

Looking at only the units, we see:

#("L"cdot"bar")/("mol"cdot"K") = (stackrel(V)overbrace("L")cdot stackrel(P)overbrace("bar"))/(stackrel(n)overbrace("mol")cdot stackrel(T)overbrace("K"))#
As before, these are clearly equivalent units. That means if you use (2), then volume is in #\mathbf("L")#, temperature is in #\mathbf("K")#, and pressure is in #\mathbf("bar")#.
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Answer 3

The temperature must be in Kelvin (K), the pressure must be in atmospheres (atm), and the volume must be in liters (L) in any gas law equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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