How do you determine the number of each type of ion in the compound made of sodium and sulfur? What is the formula of the compound?

Answer 1

The ratio of #Na^+# to #S^(2-)# must be 2 to 1
The formula is #Na_2S#

The charges on the ions that make up the compound must be ascertained. Typically, the Periodic table or standard lists can be used to obtain this information.

As you mention in the question, the objective is to guarantee that the compound will be electrically neutral. Since the Na and sulfide ions have +1 and -2 charges, respectively, the simplest ratio that yields zero net charge is 2 to 1.

The compound's empirical formula—which is what you want—will be written if you use these values as the formula's subscripts.

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Answer 2

To determine the number of each type of ion in the compound made of sodium and sulfur, you need to consider the charges of the ions. Sodium typically forms ions with a charge of +1 (Na⁺), while sulfur typically forms ions with a charge of -2 (S²⁻). To balance the charges, you need two sodium ions (2Na⁺) for every sulfur ion (S²⁻). Therefore, the formula of the compound made of sodium and sulfur is Na₂S.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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