Find the equilibrium constant for a 3-electron transfer process, whose standard emf is #"0.59 V"# at #"298.15 K"#? #F = "96485.33 C/mol e"^(-)#

#a)# #10^15#
#b)# #10^20#
#c)# #10^25#
#d)# #10^30#

Answer 1
The standard EMF (electromotive "force") is #E_"cell"^@#. So, you should relate the following two equations:
#\mathbf(DeltaG = DeltaG^@ + RTlnQ)#
#\mathbf(DeltaG^@ = -nFE_"cell"^@)#

where

Since we are finding #K_"eq"#, we know that #DeltaG = 0# and #Q = K# at equilibrium. Therefore:
#DeltaG^@ = -RTlnK_"eq" = -nFE_"cell"^@#
#=> color(blue)(K_"eq") = e^(nFE_"cell"^@"/"RT)#
#= e^(("3 mols e"^(-)"/1 mol atom"cdot"96485.33 C/mol e"^(-)cdot"0.59 V")"/"("8.314472 J/mol"cdot"K"cdot"298.15 K")#
#= e^68.89#
#~~ color(blue)(8.3xx10^(29))#
I found the actual answer to this elsewhere, and all they give is #10^30#, which is close enough, since the other given answer choices were #10^15#, #10^20#, and #10^25#.
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

The equilibrium constant (K) for a 3-electron transfer process with a standard electromotive force (emf) of 0.59 V at 298.15 K and Faraday's constant (F) of 96485.33 C/mol e^(-) can be calculated using the Nernst equation:

K = exp((-n*E°) / (RT))

Where:

  • n is the number of electrons transferred (3 in this case)
  • E° is the standard emf (0.59 V)
  • R is the gas constant (8.314 J/(mol*K))
  • T is the temperature in Kelvin (298.15 K)

Substituting the values:

K = exp((-3 * 0.59) / (8.314 * 298.15))

K ≈ exp(-1.7746 / 2477.883)

K ≈ exp(-0.000715)

K ≈ 0.9993

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7