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A particular type of hops contains 15.4 % m/m acids. If 25 mL of methanol contains 1.00 g of hops, what is the percent by mass of acids in the solution?

The density of methanol is 0.792 g/mL.

Answer 1

The concentration of the acids in the methanol is 0.921 % by mass.

18.4% of the hops are acidic.

#"Mass of acids" = 1.00 color(red)(cancel(color(black)("g hops"))) × "18.4 g acids"/(100 color(red)(cancel(color(black)("g hops")))) = "0.184 g acids"#

#"Mass of methanol" = 25 color(red)(cancel(color(black)("mL"))) × "0.792 g"/(1color(red)(cancel(color(black)("mL")))) = "19.8 g"#

#"Mass of acids + methanol" = "0.184 g + 19.8 g" = "19.984 g"#

The mass percent formula is

#color(blue)(bar(ul(|color(white)(a/a) "Mass %" = "Mass of component"/"Total mass" × 100 %color(white)(a/a)|)))" "#

∴ #"Mass % of acids" = (0.184 color(red)(cancel(color(black)("g"))))/(19.984 color(red)(cancel(color(black)("g")))) × 100 % = 0.921 %#

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Answer 2

Peyton Adams

The percent by mass of acids in the solution is 0.615%.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.