Why are combustion reactions taught as BOTH word equations, and symbol equations?

Answer 1

Why, because teachers and educators have found this to be the most efficient, most intuitive method.

I believe—though I could be mistaken—that you are referring to combustion reactions, in which a hydrocarbon burns entirely or partially with oxygen to produce carbon dioxide and water. Accordingly, for pentane, we write:

#"Pentane + oxygen "rarr" carbon dioxide + water"#

If this were our intention, which it is!, we would write the imbalanced equation as follows:

#C_5H_12 + O_2 rarr CO_2 + H_2O#

Thus, maintain a carbon balance:

#C_5H_12 + O_2 rarr 5CO_2 + H_2O#

Furthermore, the hydrogen:

#C_5H_12 + O_2 rarr 5CO_2 + 6H_2O#

Next, the oxygen

#C_5H_12 + 8O_2 rarr 5CO_2 + 6H_2O#

Thus, the carbons, hydrogens, and oxygens have all been balanced in order to produce the stoichiometrically balanced equation. However, this can occasionally cause issues when applied to even-numbered alkanes.

#C_6H_14 + 19/2O_2 rarr 6CO_2 +7H_2O#

Some would argue that the equation should be doubled to get: since you cannot have half integral coefficients.

#2C_6H_14 + 19O_2 rarr 12CO_2 +14H_2O#
I prefer the first equation with its half integral coefficient, because I find that the arithmetic is easier to rationalize and intuit in a subsequent calculation where given masses are reacted. Whichever method you choose, both mass and charge must be conserved, and #"GARBAGE IN "-=" GARBAGE OUT"#.
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Answer 2

Combustion reactions are taught using both word equations and symbol equations to provide a comprehensive understanding of the chemical process involved. Word equations describe the reaction in a descriptive form using words, while symbol equations represent the reaction using chemical symbols and formulas, which is more precise and allows for quantitative analysis. This dual approach helps students grasp both the conceptual and mathematical aspects of combustion reactions.

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Answer 3

Combustion reactions are taught as both word equations and symbol equations to provide a comprehensive understanding of the chemical process. Word equations help in understanding the reaction conceptually by describing the reactants and products in words. Symbol equations, on the other hand, provide a precise representation of the reaction using chemical symbols and formulas. Both formats are essential as they cater to different learning styles and levels of understanding. Additionally, symbol equations are crucial for communication within the scientific community as they provide a standardized notation that is universally understood.

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Answer 4

Combustion reactions are taught using both word equations and symbol equations to provide a comprehensive understanding of the reaction. Word equations describe the reaction using words, which helps learners understand the substances involved and the overall process. Symbol equations, on the other hand, use chemical symbols and formulas to represent the reaction more precisely, showing the chemical formulas of reactants and products and indicating the balanced nature of the reaction. By learning both types of equations, students gain a deeper comprehension of combustion reactions and develop the skills necessary for communicating and manipulating chemical reactions effectively.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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