A cyclist is going at 4 kmph and takes them #t# less than #14# hours to get to their destination. On the trip back they take the same route, but at #10 kmph# and make it back in #t# hours. Using a diagram, how do you find the value of #t#?
Here's your diagram
Thus, it took her 4 hours to bike and 10 hours to walk.
Hopefully this helps!
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You can use a distance-time diagram to represent the two trips. Since the distance is the same for both trips, you can set up an equation where the distance equals the speed multiplied by the time. Then, solve for t.
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To find the value of t, we can use the formula:
Distance = Speed × Time
Since the distance traveled in both directions is the same, we can set up the equation:
Distance (going) = Distance (returning)
Using the formula:
Speed × Time (going) = Speed × Time (returning)
Given that the cyclist goes at 4 kmph on the trip there and 10 kmph on the trip back, and that it takes less than 14 hours to get to the destination and t hours to return, we can set up the equation as follows:
4 × (14 - t) = 10 × t
Now, solve for t.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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