How many atoms in a #25.0*g# mass of water?

Answer 1

We calculate the number of moles of water, and then multiply this number by #3N_A#

#"Moles of water"# #=# #(25.0*g)/("18.01 "g*mol^-1)# #=# #1.39*mol.#
In each mole of water there are #3# #mol# atoms.
So #"Number of atoms"# #=# #1.39*molxxN_Axx3" atoms "mol^-1# #=# #4.16xxN_A " atoms"#.
#N_A = "Avogadro's number"# #=# #6.022xx10^23#
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Answer 2

The molar mass of water (H2O) is approximately 18.015 g/mol. Using this molar mass, we can calculate the number of moles of water: Number of moles = Mass / Molar mass Number of moles = 25.0 g / 18.015 g/mol ≈ 1.388 moles Since 1 mole of water contains 6.022 x 10^23 molecules (Avogadro's number), we can calculate the number of molecules in the given mass: Number of molecules = Number of moles × Avogadro's number Number of molecules = 1.388 moles × 6.022 x 10^23 molecules/mol ≈ 8.37 x 10^23 molecules Since each water molecule contains three atoms (2 hydrogen atoms and one oxygen atom), we can calculate the total number of atoms: Total number of atoms = Number of molecules × N

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Answer 3

To find the number of atoms in a 25.0 g mass of water (H₂O), follow these steps:

  1. Calculate the Molar Mass of Water:

    • Hydrogen (H) has an atomic mass of approximately 1.01 g/mol.
    • Oxygen (O) has an atomic mass of approximately 16.00 g/mol.
    • Water (H₂O) has a molar mass of (2(1.01) + 16.00 = 18.02) g/mol.
  2. Calculate the Moles of Water in 25.0 g:

    • Moles of water = mass of water / molar mass of water.
    • Moles of water = (25.0 , \text{g} / 18.02 , \text{g/mol}) ≈ 1.387 moles of water.
  3. Calculate the Number of Molecules of Water:

    • Avogadro's number = (6.022 \times 10^{23}) molecules/mol.
    • Number of water molecules = (1.387 , \text{moles} \times 6.022 \times 10^{23} , \text{molecules/mol}).
    • Number of water molecules ≈ (8.35 \times 10^{23}) molecules.
  4. Calculate the Total Number of Atoms in the Water Mass:

    • Each water molecule consists of 3 atoms (2 hydrogen atoms and 1 oxygen atom).
    • Total number of atoms = (8.35 \times 10^{23} , \text{molecules} \times 3 , \text{atoms/molecule}).
    • Total number of atoms ≈ (2.51 \times 10^{24}) atoms.

Therefore, a 25.0 g mass of water contains approximately (2.51 \times 10^{24}) atoms.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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