What is the molar concentration of sulfuric acid is we have an #"80% w/w"# concentration with #rho_"solution"=1.73gmL^-1#?

Answer 1

Wyatt Atkins

Approx. #14# #mol*L^-1#

We know that #1# #mL# of sulfuric acid has a mass of #1.73# #g#, of which #1.384# #g# is #H_2SO_4#.

So #"concentration"# #=# #"Moles of solute"/"Volume of solution"#

#(1.384*cancelg)/(98.079*cancelg*mol^-1)# #xx# #1/(1*cancel(mL)xx(10^-3L*cancel(mL^-1))# #=# #?? mol*L^-1#

#"98% sulfuric acid (w/w)"# has a density of #1.83*g*mL^-1#. What is the molarity of this solution.

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Answer 2

Naomi Aronson

Calculate molar concentration using the given information:

Molar concentration of sulfuric acid = (80% w/w) * (rho_solution / molar mass of H₂SO₄) * 10

Substitute the values:

Molar concentration = (0.80) * (1.73 g/mL / 98.08 g/mol) * 10

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

What is the molar concentration of sulfuric acid is we have an #"80% w/w"# concentration with #rho_"solution"=1.73*g*mL^-1#?

What is the molar concentration of sulfuric acid is we have an #"80% w/w"# concentration with #rho_"solution"=1.73gmL^-1#?