What is the electronic structure with respect to carbon in calcium carbide, #Ca^(2+)C_2^(-)#?

Answer 1

The answer is 1: 6 electrons

Easy: In a question like this, the number of protons ALWAYS equals the number of electrons.

Since neutrons are chargeless, the only remaining elements are protons, which have a positive charge, and electrons, which have a negative charge. This carbon atom is neutral.

The atom must be neutral in this instance, even though the protons have a charge of +6.

Hence, six electrons are required. The atom's charge is zero because electrons -6 and +6 cancel each other out.

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Answer 2

The carbide anion is actually #:C-=C:^(2-)#, and typically occurs as #CaC-=C#, its calcium salt.

I'd be interested in the proffered answer, but the question is poorly formulated; each carbon nucleus has seven electrons surrounding it.

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Answer 3

Since each carbon atom in the C2^(-) ion has four valence electrons, the electronic structure of the carbon atom in calcium carbide (Ca^(2+)C2^(-)) is similar to that of a carbon atom in a covalent compound, meaning that the electronic structure of carbon in calcium carbide is 1s^2 2s^2 2p^2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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