Is #X+Y=C+D# a correct chemical equation?

Answer 1

To begin with, you write #X+Y->C+D#
In stead of an #=# sign.

And then it's easy to see that #CandD# must be the products, and #XandY# the reactants (=the compounds that react).
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Answer 2

Reactants are on the left side of the equation and products are on the right side of the equation.

Reactants are always written on the left side of a general chemical equation, such as the one you have here, and products are written on the right side.

Regarding you, you are aware that

#X + Y -> C + D#
Compound #X# will react with compound #Y# to form two products, #C# and #D#.
Since #X# and #Y# are on the left side of the equation, they will be your reactants. That makes #C# and #D# your products.
#underbrace(X + Y)_(color(green)("reactants")) -> overbrace(C + D)^(color(blue)("products"))#

The reactants and products will still be on the left and right sides of the equation, even in the case of a reverse reaction.

In your situation, you may have

#C + D -> X + Y#
This time #C# and #D# will react to form #X# and #Y#.

Thus keep in mind that a chemical reaction is always expressed as follows.

#color(green)("Reactants") -> color(blue)("Products")#
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Answer 3

X+Y=C+D is a mathematical expression rather than a chemical equation, so it is not a valid chemical equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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