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What was the heat lost to the surroundings if #"11.3 g"# of diamond is cooled from #38.7^@ "C"# to #21.3^@ "C"#?

Answer 1

Olivia Anton

Well, if ever you're lucky enough to get this much diamond... the specific heat capacity of diamond is available here.

It is approximately #"516 J/kg"^@"C"# or #"0.516 J/g"^@"C"#.

Thus, using the equation for heat transfer at constant pressure:

#q = mcDeltaT = mc(T_f - T_i)#

where:

So,

#q = ("11.3 g")("0.516 J/g"^@ "C")(21.3^@"C" - 38.7^@"C")#

#= -101.456 -> -"102 J"#

Since the temperature dropped, heat transferred out of diamond. To account for the sign...

#=# #"102 J lost"# to the surroundings.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.