# What is the equation of the tangent to the line #sf(y=ln(x^2-8)# at the point (3,0) ?

To find the equation of the tangent we must find the first derivative of the function. To do this we must use the chain rule (function of a function).

This states that:

So the equation of the tangent is:

The situation looks like this:

graph{(ln(x^2-8)-y)(6x-18-y)=0 [-10, 10, -5, 5]}

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The equation of the tangent to the line sf(y=ln(x^2-8) at the point (3,0) is y = -3x + 9.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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