# What volume of diluent must I add to 1 mL of a 4 mg/L solution of dexamethasone to get a concentration of 2.5 mg/L? Bonus: What volume of the diluted solution contains 0.35 mg of dexamethasone?

One milliliter of diluent is required.

The formula is available for use.

You need to add (1.6 -1) mL = 0.6 mL of diluent because you started with 1 mL and want 1.6 mL of diluted solution.

Bonus:

Thus, 0.35 mg of dexamethasone will be present in 0.14 mL of the diluted solution.

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To dilute 1 mL of a 4 mg/L solution of dexamethasone to a concentration of 2.5 mg/L, you need to add 0.625 mL of diluent.

To find out what volume of the diluted solution contains 0.35 mg of dexamethasone, you can set up a proportion:

(0.35 mg) / (2.5 mg/L) = (x mL) / (1 mL + 0.625 mL)

Solving for x, you get x ≈ 0.237 mL. Therefore, approximately 0.237 mL of the diluted solution contains 0.35 mg of dexamethasone.

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To dilute 1 mL of a 4 mg/L solution of dexamethasone to a concentration of 2.5 mg/L, you need to add 0.375 mL of diluent.

To calculate the volume of the diluted solution containing 0.35 mg of dexamethasone, you can use the formula:

( \text{Volume of diluted solution} = \frac{\text{Amount of dexamethasone}}{\text{Concentration of diluted solution}} )

Plugging in the values, we get:

( \text{Volume of diluted solution} = \frac{0.35 \text{ mg}}{2.5 \text{ mg/L}} = 0.14 \text{ mL} )

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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